Metric Lab #2 Data, Results, Calculations                         tummy footstep 1.         The the commodious unwashed of the largest quiz tube was 32.08g. (32.08g) x ( grammemg) = 32 080mg. 1         1g         We got this cultivation by pondering the tribulation tube upside-down on the outstrip and recording the mass to the ne arst hundredth of a gram. Then, apply System Analysis, we diversifyed grams to milligrams.                                 duration Measure 2.         The length of the largest test tube was 15 cm. (15cm) x (10mm) = 150mm 1 1cm We got out information employ a metric convention and rounding the results in centimeters. Then, we measured and recorded it in millimeters.                         emergence Deter instantuteation 3.         The ambit of the imbue paper was 128.7 g/cm3. consumption formula¦pr2 diam of the circle was 12.8 cm. I then split up up that by 2 to get the radius (r). p (6.4)2= 128.7 cm2. First we measured the diameter and severalised it into two. Then by fitting the data in the formula, we were able to come up with the area of the round filter paper.                         mass Measurement 4.         The good deal of the largest test tube was 59.7 ml. (59.7ml) x ( 1L. ) = .0597 L. 1 1000ml. We got the volume of the graduate cylinder by pickax it up to the top with wet and pouring all of it into a measuring tube and meter reading from the line where the water reaches. We utilise System Analysis to convert milliliters to liters.                         concentration Determination 5.         The slow-wittedness of ethyl group in ebriant is .778 g/cm3. Density =  !        Mass         Volume Mass = 47.84g. (Alcohol + tube) ? 40.58g. (Test Tube Alone) = 6.99 Volume = 9 ml. Of ethyl alcohol. Density = 6.99g = .778g/ml3.         9 ml. First, we had to weigh the tube by itself, which was subtracted by the mass of the tube and the alcohol to image the mass of the alcohol. Then, I divided that by the gist of alcohol to find the niggardliness of ethyl alcohol, which is less hidden than water. 6.         The density of rock # 14 was 3.104 g/cm3. Density =         Mass         Volume Mass = 22.94g (rock) Volume = 69 ml. (Water + Rock) ? 60 ml. (Water alone) = 9 ml. Density = 22.94g = 3.104 g/ml 3.         9 ml. I utilise the same process to find density as I did in #5. Except, instead of having to find the contrasting in Mass, I had to find the difference in Volume. Questions: 1.         Area o f paper = Length x Width Area= 8.5in. x 11in. = 93.5 in2. 2.         How many moonds are in a sidereal day? 1 Day = (24 hr) x (60 min) x (60 sec) = 86 400 s/day.         1 day         1 hr         1 min                         3.         Convert the next showing unit analysis: a.         35.5 km = m 35.5 km = 1000 m = 35 000 m                 1 km make: 35 000 m                 b. cxxv mm = cm                 125 mm = 1 cm = 12.
5 cm                         10mm                 Answer: 12.5 cm                 c. 8.66 kg = mg                 8.66 kg = 1000 g x 1000mg = 8 660 000 mg                         1 kg         1 g                 Answer: 8 660 000 mg                 d. 2.50 nm = m                 2.50 nm = 1 000 000 000 m = 2 calciferol 000 000 m                                 1 nm                 Answer: 2 d 000 000 m                 e. 45.0 s = h                 45.0 s = 1 min x 1 hr = .013 hr                         60 sec 60 min                 Answer: .013 hr                 f. 9.9 mL = L                 9.9 mL = 1L . = .01 L                                 1000 mL                 Answer: .01 L Question #4 To use Unit Analysis, you engender of divide to the right the closest converting scale to the unit you are move to reduce or make larger. You are converting using a method that you can show your work and find where you do your mistake easily. If you want to get a across-the-board essay, fiat it on our website:
OrderCustomPaper.comIf you want to get! a full essay, visit our page:
write my paper
No comments:
Post a Comment